7x+4^2=12x-8

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Solution for 7x+4^2=12x-8 equation: 



7x+4^2=12x-8

We move all terms to the left:

7x+4^2-(12x-8)=0

We add all the numbers together, and all the variables

7x-(12x-8)+16=0

We get rid of parentheses

7x-12x+8+16=0

We add all the numbers together, and all the variables

-5x+24=0

We move all terms containing x to the left, all other terms to the right

-5x=-24

x=-24/-5

x=4+4/5

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